LINQ on a LinkedList - iterate over LinkedListNode<T>, not T

I'm having a problem understanding how to do someth开发者_StackOverflow社区ing in LINQ.

I have a linkedlist, the type of the object doesn't matter. What does matter is that I want to do something in a Where() based on the relationship between the current object and the next one in the list.

Why can't I do something like:

linkedlist.Where(n=>a_function(n.Value, n.Next.Value))?

What is the syntax to do this, if it's even possible? The type inference system seems to insist that I want the lambda argument to be T, not LinkedListNode<T>.

You'll have to write new iterator for linked list to do that. Something like

public static class LinkedListExtensions
{
    public static IEnumerable<LinkedListNode<T>> EnumerateNodes<T>(this LinkedList<T> list)
    {
        var node = list.First;
        while(node != null)
        {
            yield return node;
            node = node.Next;
        }
    }
}

so you can use

linkedlist.EnumerateNodes().Where(n=>a_function(n.Value, n.Next.Value))

Your issue doesn't have much to do with type-inference; LinkedList<T> is an IEnumerable<T> , not an IEnumerable<LinkedListNode<T>>. Additionally, there isn't a direct way to get a sequence of (current, next) tuples, so you'll have to implement that yourself.

Here's one (not so efficient) way with LINQ:

var filtered = linkedlist.Zip(linkedList.Skip(1),(current, next) => new {current, next} )
                         .Where(a => a_function(a.current, a.next))
                         .Select(a => a.current);

This will choose a value if the predicate matches (value, nextValue). You might have to tweak the query a bit if that isn't exactly what you need.

Otherwise, go with max's solution if you need efficiency or if you have lots of filters that are based on (node, nextNode).

Inspired by max's answer, I came up with a shorter version:

public static IEnumerable<LinkedListNode<T>> GetNodes<T>(this LinkedList<T> list)
{
    for (var node = list.First; node != null; node = node.Next)
        yield return node;
}

Or you could sacrifice readability for an even shorter version:

public static IEnumerable<LinkedListNode<T>> GetNodes<T>(this LinkedList<T> list)
    => for (var node = list.First; node != null; node = node.Next) yield return node;