Printing first four lines per key

I would like to print the first 4 lines by field 1 using awk

Input

111 1032192

111 2323476

111 1698881

111 2451712

111 2013780

112 2331004

112 1886376

112 1189765

112 1877267

Output

111 1032192

111 2323476

111 1698881

111 2451712

112 2331004

112 1886376

112 1189765

112 1877267

Thanks

Tony

awk '++count[$1] <= 4' input_file

($1 != curkey) { curkey=$1; i=0; }
(i < 4)        { i++; print; }