How do you split a string at certain character numbers in javascript?
I want a string split at every single character and put into an array. The string is:
var string = "hello";
Would 开发者_JS百科you use the .split()
? If so how?
I was researching a similar problem.. to break on every other character. After reading up on regex, I came up with this:
data = "0102034455dola";
arr = data.match(/../g);
The result is the array: ["01","02","03","44","55","do","la"]
Yes, you could use:
var str = "hello";
// returns ["h", "e", "l", "l", "o"]
var arr = str.split( '' );
If you really want to do it as described in the title, this should work:
function splitStringAtInterval (string, interval) {
var result = [];
for (var i=0; i<string.length; i+=interval)
result.push(string.substring (i, i+interval));
return result;
}
var s= "hello";
s.split("");
Here is a simple way do it with a while loop;
function splitStringAtInterval(str, len){
var len = 10;
var arr = [];
str = str.split("");
while(str.length > len){
arr.push(str.splice(position,len).join(""));
}
if(str.length > 0)arr.push(str.join(""));
return arr;
}
If you want it short and 'functional':
var input = 'abcdefghijklmn1234567890';
var arr = Array.prototype.slice.call(input), output = [];
while (arr.length) output.push(arr.splice(0, 3).join(''));
output; // ["abc", "def", "ghi", "jkl", "mn1", "234", "567", "890"]
If you don't want to use a RegExp, you can also do this instead:
const splitEvery = (nth) => (str) =>
Array.from(
{length: Math.ceil(str.length / nth)},
(_, index) => str.slice(index * nth, (index + 1) * nth)
)
// example usage:
const splitEvery2nd = splitEvery(2)
const result = splitEvery2nd('hello')
// result is: ['he', 'll', 'o']
If you want to cut off any remaining parts, replace the Math.ceil
with a Math.floor
call.
Understanding:
This function creates an Array with the length of the number of slices, containing the expected parts of the text.
精彩评论