drop a draggable using jquery
Is there any way of dropping a draggabl开发者_JAVA技巧e into the droppable by hardcoding and not by actually going into the browser and doing drag-drop??
Thanks in advance.:D
I don't know if I have understood very clearly, in any case I think it is curious perspective,if you mean to animate and do the same things if we have dragged a layer into a droppable layer.
I suppose you could do it like this:
http://www.jsfiddle.net/dactivo/QLTUS/
You use animate() to move the layer to the droppable, and then in the complete function, you imitate what normally happens in a dropping action, that is to say change the class, and there you can include whatever.
I mean it is not important the drop event, but what you execute in the drop event, that can be included in your complete event of the animation. I have encapsulated this in a function called layerDrop().
$(function() {
$( "#draggable" ).draggable();
$( "#droppable" ).droppable({
drop: function( event, ui ) {
layerDrop();
}
});
$("#btnMove").click(function()
{
$("#draggable").animate({"left": $( "#droppable" ).offset().left ,"top": $( "#droppable" ).offset().top},
{
duration: 1000, specialEasing: { width: 'linear' },
complete:function()
{
$("#message").html("Completed!");
layerDrop();
//whatever
}
}
);
});
function layerDrop(){
$( "#droppable")
.addClass( "ui-state-highlight" )
.find( "p" )
.html( "Dropped!" );
}
});
I think you mean to position a dragged option programmatically. If that is the case then look in the official jQuery draggable documentation: http://docs.jquery.com/UI/API/1.8/Draggable
It seems the short answer is:
To manipulate the position of a draggable during drag, you can either use a wrapper as the draggable helper and position the wrapped element with absolute positioning, or you can correct internal values like so:
$(this).data('draggable').offset.click.top -= x
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