Ajax retrieve data from Mysql - Not working properly
I am learning AJAX and I am trying to recreate this fairly simple example:
http://www.w3schools.com/php/php_ajax_database.asp
I created this database:
So now to recreate the example I just basically copied and pasted the code:
index.html
<html>
<head>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Juan</option>
<option value="2">Manuel</option>
</select>
</form>
<br />
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>
and getuser.php
<?php
$q=$_GET["q"];
$con = mysql_connect('localhost', 'root', 'root');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ajax_demo", $con);
$sql="SELECT * FROM user WHERE id = '".$q."'";
$result = mysql_query($sql);
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Age'] . "</td>";
echo "<td>" . $row['Hometown'] . "</td>";
echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?开发者_开发百科>
Now the strange part is that when I go to index.html I can see the age, hometown and job but not Firstname and Lastname:
I realize this might be a very basic mistake but I cant find a workaround.
I am sorry I had to paste in so much code but I did not see any other way I could explain my problem and you could help me.
Thanks a lot in advance!
You are using
FirstName LastName
instead of
Firstname Lastname
Array indices are case sensitive.
加载中,请稍侯......
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