Remove leading comma from a string

I have the following string:

",'first string','more','even more'"

I want to transform this into an Array but obviously this is not valid due to the first comma. How can I remove the first comma from my string and make it a valid Array?

I’开发者_JAVA技巧d like to end up with something like this:

myArray  = ['first string','more','even more']

To remove the first character you would use:

var myOriginalString = ",'first string','more','even more'"; 
var myString = myOriginalString.substring(1);

I'm not sure this will be the result you're looking for though because you will still need to split it to create an array with it. Maybe something like:

var myString = myOriginalString.substring(1);
var myArray = myString.split(',');

Keep in mind, the ' character will be a part of each string in the split here.

In this specific case (there is always a single character at the start you want to remove) you'll want:

str.substring(1)

However, if you want to be able to detect if the comma is there and remove it if it is, then something like:

if (str[0] == ',') { 
  str = str.substring(1);
}

One-liner

str = str.replace(/^,/, '');

I'll be back.

var s = ",'first string','more','even more'";

var array = s.split(',').slice(1);

That's assuming the string you begin with is in fact a String, like you said, and not an Array of strings.

Assuming the string is called myStr:

// Strip start and end quotation mark and possible initial comma
myStr=myStr.replace(/^,?'/,'').replace(/'$/,'');

// Split stripping quotations
myArray=myStr.split("','");

Note that if a string can be missing in the list without even having its quotation marks present and you want an empty spot in the corresponding location in the array, you'll need to write the splitting manually for a robust solution.

var s = ",'first string','more','even more'";  
s.split(/'?,'?/).filter(function(v) { return v; });

Results in:

["first string", "more", "even more'"]

First split with commas possibly surrounded by single quotes,
then filter the non-truthy (empty) parts out.

To turn a string into an array I usually use split()

> var s = ",'first string','more','even more'"
> s.split("','")
[",'first string", "more", "even more'"]

This is almost what you want. Now you just have to strip the first two and the last character:

> s.slice(2, s.length-1)
"first string','more','even more"

> s.slice(2, s.length-2).split("','");
["first string", "more", "even more"]

To extract a substring from a string I usually use slice() but substr() and substring() also do the job.

s=s.substring(1);

I like to keep stuff simple.

You can use directly replace function on javascript with regex or define a help function as in php ltrim(left) and rtrim(right):

1) With replace:

var myArray = ",'first string','more','even more'".replace(/^\s+/, '').split(/'?,?'/);

2) Help functions:

if (!String.prototype.ltrim) String.prototype.ltrim = function() {
    return this.replace(/^\s+/, '');
};
if (!String.prototype.rtrim) String.prototype.rtrim = function() {
    return this.replace(/\s+$/, '');
};
var myArray = ",'first string','more','even more'".ltrim().split(/'?,?'/).filter(function(el) {return el.length != 0});;

You can do and other things to add parameter to the help function with what you want to replace the char, etc.

this will remove the trailing commas and spaces

var str = ",'first string','more','even more'";
var trim = str.replace(/(^\s*,)|(,\s*$)/g, '');

remove leading or trailing characters:

function trimLeadingTrailing(inputStr, toRemove) {
    // use a regex to match toRemove at the start (^)
    // and at the end ($) of inputStr
    const re = new Regex(`/^${toRemove}|{toRemove}$/`);
    return inputStr.replace(re, '');
}