NP-Hard solution question

i have NP hard problem. Let imagine I have found some polynomial algorithm that find ONLY one of many existing solutions of that problem, but at least one solution (if present in the probem). Is that algorithm considered as solution of NP=P question (if that algorithm transformed to mathemat开发者_StackOverflow社区ical proof)?

Thanks for answers

NP is a class of decision problems. Your algorithm should answer "yes" or "no" correctly to all possible instances (questions).

For example, the problem: "given graph G and number k, does G contain a clique of size >= k" is NP-hard. If you have a polynomial time algorithm that answers "yes" or "no" correctly each time, then it is a valid proof of P=NP. The algorithm doesn't need to explicitly show the clique - only answer if it exists for all possible G and k.

If you find a NP-hard problem and you can detect some cases that you can solve in polynomial time (leaving others for exponential time), then only if the fraction of cases remaining is on the order of log(N)/N will you change the order of the entire problem, and even then only if you can restrict your exponential case to examining only log(N) not all N possibilities.

Also, if you find a NP-hard problem where you think you can solve every case in polynomial time, you have probably made a mistake, either in posing a NP-hard problem correctly, or in finding the more troublesome examples. Try a larger test set before believing yourself!