In C# and also Java, what's the relationship between Object[] and String[]?
I recently started to think of this problem and I can't find the answer. The following code compiles and executes as expected
object[] tes开发者_如何转开发t = new string[12];
However, I don't know why.
I mean, should we consider string[] as the derived class of object[]?
I think in C#, every array is an instance of Array class. If Array is generic, it should be Array<T>
, and Array<string>
can be assigned to Array<object>
, it doesn't make sense. I remember only interface can use in/out keyword.
And in Java, I'm not sure, but still feel weird. Why different types of references can be possibly assigned to each other when they don't have super-sub class relationship?
Can somebody explain a little?
Thanks a lot!
It's because reference type arrays support covariance in both Java and C#. It also means that every write into a reference type array has to be checked at execution time, to make sure you don't write the wrong type of element into it :(
Don't forget that both Java and C# (and .NET in general) started off without generics. If they had had generics to start with, life could have been somewhat different.
Note that both Java and C# support generic variance now, but in rather different ways. So for example in C# 4 you can write:
IEnumerable<string> strings = // Get some string sequence here
IEnumerable<object> objects = strings;
but you can't write
IList<string> strings = // Get some string list here
// Compile-time error: IList<T> isn't covariant in T
IList<object> objects = strings;
This wouldn't be safe, because you can add to an IList<T>
as well as taking items from it.
This is a big topic - for more details, see Eric Lippert's blog series.
In C# there is (and always been) covariance of arrays of reference-types. It still is a string[]
, but you can legally cast it to an object[]
(and access values as you would expect).
But try putting in an int
(or any other non-string value) and you'll see that it still behaves appropriately (i.e. doesn't let you).
This is because object is the parent (or the superclass) for all other classes. Search for boxing/ unboxing for more data.
Since all the really smart guys are talking about covariance and contravariance and I couldn't for the life of me explain (or understand) this stuff, listen to Eric Lippert:
Covariance and Contravariance FAQ
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