age from dob in sql

In the sql query, I am getting problem in the where clause.

I have a dob and ssn of people in a table. I need to find the youngest snr. customer. The age of youngest senior customer starts from 55. The data of DOB contains all the dob's of children,parent, senior customers. I开发者_如何学运维n the line "where" I have to write a condition that checks if the age is > 55 and has to be smaller amongst the senior customers.Please suggest me some ways .I posted a similar question before, but did nt get any reply that can help me in solving it.

I dont have the age parameter in my table.

SSn    DOB
22   1950-2-2
21   1987-3-3
54   1954-4-7

I need to find the ssn corresponding to the age whcih has to be greater than 55 and smaller among above values .

In the script below, the sub-select finds the DOB of the youngest person 55 years of age or over; this is then used to find the corresponding SSN record(s). [This uses SQL Server syntax.]

SELECT yt.* 
FROM *yourtable* yt
INNER JOIN 
(
    SELECT MAX(DOB) AS DOB
    FROM *yourtable*
    WHERE DATEADD(year, 55, DOB) < getdate() 
) maxdob
ON maxdob.DOB = yt.DOB

n.b. you may find more than a single record if there is more than 1 person with the same DOB. If you want to force this single restriction, add a TOP 1 clause in your SELECT statement. hth

If you have the DOB then you can easily calculate the age based on the current date:

WHERE DATE_ADD(DOB, INTERVAL 55 YEAR) < NOW()

This will add 55 years to the DOB and if it is greater than the current time, it's true. This would indicate they are at least 55 years of age.