Can you add a number to a number in a Array?
package javaapplication1;
import java.io.*;
/**
*
* @author simon
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws IOException {
NotSimple[] objArray;
BufferedReader stdin = new BufferedReader(
new InputStreamReader( System.in ) );
System.out.println( "Enter a number of objects:" );
int size;
size = Integer.parseInt( stdin.readLine() );
//Initialize objArray
objArray = new NotSimple[size];
//TODO: Implement following functions
initializeObj(objArray);
increaseData(objArray);
printObjData(objArray);
//TODO: Explain all outputs of the below function
explainOutputs();
return;
}
//TODO
//initialize every Notsimple object in the array 'a'
//to NotSimple()
//Hint: using the for loop, assign a[i] = new NotSimple();
static void initializeObj(NotSimple[] a){
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
a[i] = new NotSimple();
}
}
//TODO:
//Increase the ‘data’ member of every NotSimple object
//in the array ‘a’ by 1
static void increaseData(NotSimple[] a) {
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
a[i].setData(a[i].getData()+1);
}
}
//TODO:
//Print the data of every NotSimple object in the array ‘a’
static void printObjData(NotSimple[] a) {
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
System.out.println (a[i].getData());
}
}
//TODO explain all the outputs 1a-1f
static void explainOutputs() {
NotSimple nsObj1 = new NotSimple();
//1a
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
NotSimple nsObj2 = new NotSimple( 50,
"Another immutable string!" );
//1b
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2 = nsObj1;
nsObj2.setData(10);
nsObj1.setData(100);
//1c
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj1 = new NotSimple();
//1d
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2 = new NotSimple();
//1e
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2.setData(10);
//1f
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
}
}
class NotSimple
{
NotSimple()
{
data = 5;
str = new String( "Initialized!" );
}
NotSimple( int i, String str1 )
{
data = i;
str = str1;
}
void setData( int i )
{
data = i;
return;
}
int getData()
{
return data;
}
void setStr( String str1)
{
str = str1;
return;
}
String getStr()
{
return str;
}
private int data;
private String str;
}
I want to add 1 to the array but it doesn't wo开发者_开发技巧rk. I get the following compilation error:
operator ++ cannot be applied to javaapplication1.NotSimple
Use
for (int i = 0; i < a.length; i++)
{
a[i].setData(a[i].getData()+1);
}
Since Java does not support operator overloading, you'll need to retrieve the old value (i.e. the getData() call), add 1 to it, and set it as the new value (i.e. the setData() call).
What does the NotSimple class look like?
Is NotSimple a numeric type that can be incremented so?
If NotSimple has a field called 'data' then replace a[i]++ with a[i].data++
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