Difference between dates [duplicate]

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Difference between dates

How to calculate the date difference between 2 dates using php

So, I have two dates. For instance, 2010-09-24 and 2010-09-25. I want to check if between those two dates the difference is 1 day.

I don't need to get a valu开发者_Python百科e of 86400 which means one day in seconds.

Don't forget that it can be 28, 28, 29, 30, 31 days in month.

Thanks.

What I have right now, but it doesn't work when there is difference between months:

$strto = strtotime($date);
$d1 = date('d', $strto);
$d2 = date('d', time());
echo $d2- $d1;

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You can use strtotime to get the number of seconds in between

echo abs(strtotime('2010-09-24') - strtotime('2010-09-25'));

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Don't use the day value - (eg date('d', ...)) - leave it as an integer (the result of strtotime()). Then subtract those dates, and then get the floor(difference / 86400).

Like so:

$dt = strtotime($date);
echo floor(abs(time() - $dt) / 86400);

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You can do this nicely with the DateTime class if you have PHP 5.3:

<?php

$datetime1 = new DateTime('2010-09-25');
$datetime2 = new DateTime('2010-09-26');

$interval = $datetime1->diff($datetime2);

$intervaldays = (int) $interval->format('%R%d'); // %R signs the result +/-

This is probably less efficient than using strtotime methods, but it is very readable.

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Why are you using date('d'... which returns the day of the month?

strtotime will create a UNIX-timestamp which is exactly what time() returns, so abs(time() - strtotime($date)) should already do the job. This way you don't have to worry how many days a month has as you're only working with timestamps.

This will get you the number of (complete) days:

floor( abs(time() - strtotime($date)) / 86400 )