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row with minimum value of a column

Having this selection:

id IDSLOT  N_UM
------------------------
1  1  6
2  6  2
3  2  1
4  4  1
5  5  1
6  8  1
7  3  1
8  开发者_开发技巧7  1
9  9  1
10  10  0

I would like to get the row (only one) which has the minimun value of N_UM, in this case the row with id=10 (10 0).


select * from TABLE_NAME order by COLUMN_NAME limit 1


I'd try this:

SELECT TOP 1 *
FROM TABLE1
ORDER BY N_UM

(using SQL Server)


Try this -

 select top 1 * from table where N_UM = (select min(N_UM) from table);


Use this sql query:

select id,IDSLOT,N_UM from table where N_UM = (select min(N_UM) from table));


Method 1:

SELECT top 1 * 
FROM table 
WHERE N_UM = (SELECT min(N_UM) FROM table);

Method 2:

SELECT * 
FROM table 
ORDER BY N_UM 
LIMIT 1

A more general solution to this class of problem is as follows.

Method 3:

SELECT *
FROM table 
WHERE N_UM IN (SELECT MIN(N_UM) FROM table);


Here is one approach

Create table #t (
id int,
IDSLOT int,
N_UM int
)
insert into #t ( id, idslot, n_um )
VALUES (1, 1, 6),
 (2,6,2),
 (3,2,1),
 (4,4,1),
 (5,5,1),
 (6,8,1),
 (7,3,1),
 (8,7,1),
 (9,9,1),
 (10, 10, 0)

 select Top 1 *
 from #t
 Where N_UM = ( select MIN(n_um) from #t )


select TOP 1  Col , COUNT(Col) as minCol from employee GROUP by Col
order by mindep  asc
0

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