select a node with an xmlns?
I am trying to select all of the links in a xhtml document in xsl. Some of the anchor tags have the namespace declaration xmlns="http://www.w3.org/1999/xhtml" in them. These are not selected. e.g. with this xml doc:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<root>
<item>
this iz sum text and it haz sum <a xmlns="http://www.w3.org/1999/xhtml" href="http://cheezburger.com/">linx</a> in it.
Teh linx haz piks of <a href="http://ica开发者_Python百科nhascheezburger.com/">kittehs</a> in dem.
</item>
</root>
and this xsl:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml">
<dl>
<xsl:for-each select="//root/item/a">
<dd><xsl:value-of select="."/></dd>
<dt><xsl:value-of select="@href"/></dt>
</xsl:for-each>
</dl>
</html>
</xsl:template>
</xsl:stylesheet>
Only the second link is selected. Can someone explain what is going on here and how I might fix it?
If you need both nodes, which are in different namespaces, use:
/root/item/*[local-name() = 'a']
However, this should seldomly happen, normally, you want a node from only one namespace:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:example="http://www.w3.org/1999/xhtml"
>
....
<xsl:for-each select="/root/item/example:a">
The a elements are in 2 different namespaces, the default namespace and the xhtml namespace. If you move the XPath outside of the xhtml formatting, you can use both namespaces to search:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:variable name="links" xmlns:xhtml="http://www.w3.org/1999/xhtml"
select="//root/item/(a | xhtml:a)"/>
<html xmlns="http://www.w3.org/1999/xhtml">
<dl>
<xsl:for-each select="$links">
<dd><xsl:value-of select="."/></dd>
<dt><xsl:value-of select="@href"/></dt>
</xsl:for-each>
</dl>
</html>
</xsl:template>
</xsl:stylesheet>
加载中,请稍侯......
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