SQL query to obtain a count of how many items have each possible value for a given column

Okay, so I have a (SQLite) table called log wherein one column (time) is a Unix epoch timestamp (the other columns are irrelevant for my purposes). These are timestamped log entries.

I am trying to get a count of how many items are logged per hour (all-time -- I don't care to do it only for a given day or whatever; I'm trying to get an idea of activity density throughout the average day). I have been successful in basically binning these into hours with the query SELECT STRFTIME('%H', DATETIME(time, 'unixepoch', 'localtime')) FROM log;, which then 开发者_如何学Gogives me just a huge list of numbers 0-23 which I can run through uniq -c to get a count of events per hour.

However (more out of stubbornness than any practical need, I admit), I want to do this counting step in SQL. My brain got me as far as knowing I'd prrroooobably have to do some kind of self-join to get only the unique values for the generated hours column, but that's where it crapped out D: Any ideas?

SELECT STRFTIME('%H', DATETIME(time, 'unixepoch', 'localtime')), 
COUNT(anotherField)
FROM log
GROUP BY STRFTIME('%H', DATETIME(time, 'unixepoch', 'localtime'));

Note: I haven't worked with SQLite. However, it supports GROUP BY and hence, this should work.

why use COUNT(anotherField)?

Use SELECT [your expression], COUNT(*) FROM log GROUP BY [your expression]