Google Sitemap Problem
I submitted a sitemap to Google and I got this error.
Incorrect namespace Your Sitemap or Sitemap index file doesn't properly declare the namespace. Expected: http://www.google.com/schemas/sitemap-image/1.1 Found: http://www.sitemaps.org/schemas/sitemap-image/1.1
I thought that 开发者_JAVA百科sitemaps.org was okay. I took it from Google's example:
Google's sitemap example
What am I doing wrong? Any ideas?
Have you tried replacing
http://www.sitemaps.org/schemas/sitemap-image/1.1
with
http://www.google.com/schemas/sitemap-image/1.1
since that seem to be problem?
If you have and that didn't help, can you post your sitemap here? Include just a few url tags.
Update: This page may be of use: http://www.sitemaps.org/protocol.php. It's where I started when I wrote my first sitemap.
Another thought: In case you don't link directly to images or videos but only to html pages or php pages, you probably can remove
xmlns:image="http://www.sitemaps.org/schemas/sitemap-image/1.1"
and
xmlns:video="http://www.sitemaps.org/schemas/sitemap-video/1.1
I'm not using that code in my sitemap, and it works as it should.
Hello, Actually the solution was replacing this:
<sitemapindex xmlns:xsi="https://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="https://www.sitemaps.org/schemas/sitemap/0.9/ https://www.sitemaps.org/schemas/sitemap/0.9/siteindex.xsd"
xmlns="https://www.sitemaps.org/schemas/sitemap/0.9">
With this:
<sitemapindex xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">
And it works as expected and Google sitemap can be able to read the file.
Thank you
XML namespaces are used for providing uniquely named elements and attributes in an XML document.
Name conflicts in XML can easily be avoided using a name prefix.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/"> <html> <body> <h2>My CD Collection</h2>
<table border="1">
<tr>
<th style="text-align:left">Title</th>
<th style="text-align:left">Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
</tr>
</xsl:for-each> </table> </body> </html> </xsl:template>
</xsl:stylesheet>
加载中,请稍侯......
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