Determining even/odd numbers (integers)?

开发者_JAVA技巧I feel stupid asking such a simple question, but is there an easy way to determine whether an Integer is even or odd?

if ((n % 2) == 0) {
    // number is even
}

else {
    // number is odd
}

It's not android specific, but a standard function would be:

boolean isOdd( int val ) { return (val & 0x01) != 0; }

Many compilers convert modulo (%) operations to their bitwise counterpart automatically, but this method is also compatible with older compilers.

You can use modular division (technically in Java it acts as a strict remainder operator; the link has more discussion):

if ( ( n % 2 ) == 0 ) {
    //Is even
} else {
    //Is odd
}

If you do a bitwise-and with 1, you can detect whether the least significant bit is 1. If it is, the number is odd, otherwise even.

In C-ish languages, bool odd = mynum & 1;

This is faster (performance-wise) than mod, if that's a concern.

When somehow % as an operator doesn't exist, you can use the AND operator:

oddness = (n & 1) ? 'odd' : 'even'

Similar to others, but here's how I did it.

boolean isEven = i %2 ==0;