jquery mouse out and mouse leave problem
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" dir="ltr">
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.0/jquery.min.js" type="text/javascript"></script>
</head>
<body>
<div id="popupContact" style="position:absolute;left:100px;top:100px;width:100px;height:50px;background-color:orange;border:1px solid red ;">
</div>
<div id="divtoshow" style="display:none;background-color:green; border:1px solid black;width:200px;height:100px;position:absolute;">
dsfdssd <div><a href="#">rahul</a></div>
</div>
</body>
</html>
<script type='text/javascript'>
$(document).ready(function(){
var popup_pos=$('#popupContact').offset();
var timer;
$("#popupContact").mouseover(function() {
if(timer) {
clearTimeout(timer);
timer = null
}
timer = setTimeout(function() {
if(!$("#VersionSelectField").is(':hidden')){
$("#divtoshow").css('position',"absolute");
$("#divtoshow").css('top',popup_pos.top-20);
$("#divtoshow").css('left',popup_pos.left-20);
$("#divtoshow").show();
$("#popupContact").hide();
}
}, 1000);
});
$("#divtoshow").mouseleave(function() {
if(timer) {
clearTimeout(timer);
timer = null
}
timer = setTimeout(function() {
$("#divtoshow").hide();
$("#popupContact").show();
}, 500);
});
});
</script>
hi i have following code , when i mouse over the popupcontact div and suddenly mouse out the div then also the divtoshow div is being shown but i dont want that please help ......
Q:how to not to show divto开发者_运维知识库show div while is i suddenly mouseout the popupcontact div ?
i want the delayWhat about
$("#popupContact").mouseout(function() {
$("#divtoshow").hide();
$("#popupContact").show();
});
?
change 500 to 0 in setTimeOut() in mouseleave()
加载中,请稍侯......
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