How to set Grid row and column positions programmatically
I have two Grids inside a Stackpanel. The first grid is named as GridX. Initially, inside the grid, there is a 2D array of Textboxes(RowDefs/ColumnDefs). The TextBox definition in XAML is
<TextBox x:Name="A1" Grid.Row="4" Grid.Column="5" TextAlignment="Center" />
I want to add a TextBlock programmatically in the same position as part of GridX.
The effect must be like this
<TextBlock Grid.Row="4" Grid.Column="5"
HorizontalAlignment="Left" VerticalAlignment="Top" Text="10" FontSize="8"/>
How to add this. I have tried this:
TextBlock tblock = new TextBlock();
GridX.SetColumn(tblock, cIndex);
GridX.SetRow(tblock, rIndex);
But failed.
Again I tried this:
int rIndex = Grid.GetRow(txtBox);
int cIndex = Grid.GetColumn(txtBox);
TextBlock tblock = new TextBlock();
tblock.VerticalAlignment = VerticalAlignment.Top;
tblock.HorizontalAlignment = HorizontalAlignment.Left;
tblock.FontSize = 8;
tblock.Text = rc[i, j - 1];
Grid.SetColumn(tblock, cIndex);
Grid.SetRow(tblock, rIndex);
txtBox.MaxLength = 1;
Now the problem is that TextBlock is not visible. TextBox hides it. I 开发者_Go百科appreciate your help.
For attached properties you can either call SetValue on the object for which you want to assign the value:
tblock.SetValue(Grid.RowProperty, 4);
Or call the static Set method (not as an instance method like you tried) for the property on the owner type, in this case SetRow:
Grid.SetRow(tblock, 4);
Here is an example which might help someone:
Grid test = new Grid();
test.ColumnDefinitions.Add(new ColumnDefinition());
test.ColumnDefinitions.Add(new ColumnDefinition());
test.RowDefinitions.Add(new RowDefinition());
test.RowDefinitions.Add(new RowDefinition());
test.RowDefinitions.Add(new RowDefinition());
Label t1 = new Label();
t1.Content = "Test1";
Label t2 = new Label();
t2.Content = "Test2";
Label t3 = new Label();
t3.Content = "Test3";
Label t4 = new Label();
t4.Content = "Test4";
Label t5 = new Label();
t5.Content = "Test5";
Label t6 = new Label();
t6.Content = "Test6";
Grid.SetColumn(t1, 0);
Grid.SetRow(t1, 0);
test.Children.Add(t1);
Grid.SetColumn(t2, 1);
Grid.SetRow(t2, 0);
test.Children.Add(t2);
Grid.SetColumn(t3, 0);
Grid.SetRow(t3, 1);
test.Children.Add(t3);
Grid.SetColumn(t4, 1);
Grid.SetRow(t4, 1);
test.Children.Add(t4);
Grid.SetColumn(t5, 0);
Grid.SetRow(t5, 2);
test.Children.Add(t5);
Grid.SetColumn(t6, 1);
Grid.SetRow(t6, 2);
test.Children.Add(t6);
for (int i = 0; i < 6; i++)
{
test.ColumnDefinitions.Add(new ColumnDefinition());
Label t1 = new Label();
t1.Content = "Test" + i;
Grid.SetColumn(t1, i);
Grid.SetRow(t1, 0);
test.Children.Add(t1);
}
Try this:
Grid grid = new Grid(); //Define the grid
for (int i = 0; i < 36; i++) //Add 36 rows
{
ColumnDefinition columna = new ColumnDefinition()
{
Name = "Col_" + i,
Width = new GridLength(32.5),
};
grid.ColumnDefinitions.Add(columna);
}
for (int i = 0; i < 36; i++) //Add 36 columns
{
RowDefinition row = new RowDefinition();
row.Height = new GridLength(40, GridUnitType.Pixel);
grid.RowDefinitions.Add(row);
}
for (int i = 0; i < 36; i++)
{
for (int j = 0; j < 36; j++)
{
Label t1 = new Label()
{
FontSize = 10,
FontFamily = new FontFamily("consolas"),
FontWeight = FontWeights.SemiBold,
BorderBrush = Brushes.LightGray,
BorderThickness = new Thickness(2),
HorizontalContentAlignment = HorizontalAlignment.Center,
VerticalContentAlignment = VerticalAlignment.Center,
};
Grid.SetRow(t1, i);
Grid.SetColumn(t1, j);
grid.Children.Add(t1); //Add the Label Control to the Grid created
}
}
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