Why is the return value of this PHP function zero for a long array?

When the row['error'] is bigger than 35, the value isn't present and the result of the function is 0. Where is the problem?

<?php
    if ($row['error'] == "")
    {
        $error = "0";
    }
    else
    {开发者_开发问答
        $error = $row['error'];
    }

    if ($row['error'] != "")
    {
       if (strlen($error) > 35)
       {
           $error = substr($row['error'],0,32) + "...";
       }
       else
       {
           $error = $row['error'];
       }
    }
?>

Change

$error = substr($row['error'],0,32) + "...";

to:

$error = substr($row['error'],0,32) . "...";

The concatenate operator in PHP isn't a plus (+) sign; it's a period (.) sign

All this code is not necessary. The second condition is redundant, and it doubles the else condition from the above. Make it all with just these few lines of code:

<?php
    $error = $row['error'];
    if (strlen($error) > 35) {
        $error = substr($row['error'],0,32) . "...";
    }
?>

Because you check:

if(strlen($error) > 35) {
}