Overrible predefined Bash variables with arguments

Can someone point me out what is the proble开发者_如何学Pythonm when I want to overrible a default value in a variable with an argument in Bash? The following code doesn't work:

#!/bin/bash

VARIABLE1="defaultvalue1"
VARIABLE2="defaultvalue2"

# Check for first argument, if found, overrides VARIABLE1
if [ -n $1 ]; then
    VARIABLE1=$1
fi
# Check for second argument, if found, overrides VARIABLE2
if [ -n $2 ]; then
    VARIABLE2=$2
fi

echo "Var1: $VARIABLE1 ; Var2: $VARIABLE2"

I want to be able to do:

#./script.sh
Var1: defaultvalue1 ; Var2: defaultvalue2
#./script.sh override1
Var1: override1 ; Var2: defaultvalue2
#./script.sh override1 override2
Var1: override1 ; Var2: override2

Thanks in advance :)

You're missing the fi for the first if. But actually you're in luck: there's an easier way to do what you're doing.

VARIABLE1=${1:-defaultvalue1}
VARIABLE2=${2:-defaultvalue2}

From man bash:

${parameter:-word}
Use Default Values. If parameter is unset or null, the expansion of word is substituted. Otherwise, the value of parameter is substituted.