command line cURL works but php one doesnt
The code:
// That works pretty well
curl -d "user%5Blogin%5D=some%40email.pl&user%5Bpass%5D=testpass&user%5Bmemory%5D=on&user%5Bsubmit%5D=Login" -L -c cookie.txt http://turbobit.net/user/login
//But this PHP code doesn't
$headers = array('Content-Type' => 'application/x-www-form-urlencoded', 'Referer' => 'http://turbobit.net/');
$postdata = array('user%5Blogin%5D' => 'some%40email.pl', 'user%5Bpass%5D' => 'test', "user%5Bsubmit%5D" => 'Login', 'user%5Bmemory%5D' => 'on');
$cookie = "/srv/http/test/regexturbobit/cookie.txt";
$c = curl_init('ht开发者_运维百科tp://tutbobit.net/user/login');
curl_setopt ($c, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6");
curl_setopt($c, CURLOPT_POST, 1);
curl_setopt ($c, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($c, CURLOPT_FOLLOWLOCATION,1);
curl_setopt($c, CURLOPT_POSTFIELDS, $postdata);
curl_setopt ($c, CURLOPT_COOKIEJAR, $cookie);
$output=curl_exec($c);
curl_close($c);
print_r($output);
it just doesn't show anything and even dont save cookie...
Try:
$postdata = 'user%5Blogin%5D=some%40email.pl&user%5Bpass%5D=testpass&user%5Bmemory%5D=on&user%5Bsubmit%5D=Login';
You shouldn't have URLencoded keys in a postdata array as they'll be URL-encoded again. Alternatively you could do:
$postdata = array(
'user[login]' => 'some@email.pl',
'user[pass]' => 'test',
// the rest of the vars here...
);
But note that passing an array for $postdata
will not send a URL-encoded request, it will send a request with multipart/form-data
encoding. From the PHP docs:
CURLOPT_POSTFIELDS
The full data to post in a HTTP "POST" operation. To post a file, prepend a filename with @ and use the full path. This can either be passed as a urlencoded string like 'para1=val1¶2=val2&...' or as an array with the field name as key and field data as value. If value is an array, the Content-Type header will be set to multipart/form-data.
So, if you pass an array, the values and keys should not already be URLEncoded.
When you provide the data as a hash array, the POST will not be a "normal" POST anymore but it will instead make a multipart formpost.
Multipart formposts (RFC1867) are very different than the normal -d one your command line uses.
A nice trick is to use append "--libcurl example.c" to your curl command line to get to see the C source code for what could be used to run the same operation.
Try using this: http://github.com/shuber/curl
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