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Force an Integer To Be At Least 2 Digits Long [closed]

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Can someone give me code to do the following....

if the integer is 1-9 display a string 01,02,03 etc.. if 10 or over leave it as is.

string display = yourInt.ToString("00"); 

DOES NOT WORK


string display = yourInt.ToString("00");


Or, in String.Format syntax (used in Console.WriteLine, for example)

string s = String.Format("{0:00}", yourInt);


I don't see why .ToString("00") didn't work. This test succeeds...

[TestMethod]
public void RightPadIntegersWithZero() {
  var values = new [] { -100, -20, -1, 0, 1, 5, 10, 100, 567 };
  var expecteds = new [] { "-100", "-20", "-01", "00", "01", "05", "10", "100", "567" };

  for (var i = 0; i < values.Length; i++) {
    var value = values[i];
    var expected = expecteds[i];

    var result = value.ToString("00");
    Assert.AreEqual(expected, result);
  }
}

You must be doing something different than what your question describes


In any language (at least the ones i know) and integer value type will never have 2 digits length in any value below 10.

To display it with always a two digits length (as 02, 05, 12) you must convert your number to String and then padding it with 0.

Or you will evaluate it like:

String newValue = String.Format("{0:00}", yourInt);

As you see you will have to convert it to string before displaying it...


Your question is a bit ambiguous: display it where?

In any case, you will probably want to look at String.Format.


Would this do what you want?

for (int i = -20; i < 100; i++)
{
 string s = i.ToString();
 while (s.Length < 2) s = "0" + s;
 Console.WriteLine(s);
}

I realize it's a bit of a brute force approach as written here. But if it did the trick, you could optimize it with a reusable character array instead of appending the string.

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