exception handling in C++

i have the following program using exception handling.

#include<iostream.h>
#include<conio.h>

void divide(int x,int y,int z)
{
  cout<<"\n Inside function 1 \n";

  if((x-y)!=0)
  {
    int R=z/(x-y);
    cout << "Result =" << R<<"\n";
  } // end of if
  else
  {
    throw(x-y);
  }  // end of else
}   // end of void

int main()
{
  try
  {
    cout<< "Inside try block\n";
    divide(10,20,30开发者_开发百科);
    divide(10,10,20);
  } //end of try
  catch(int i)
  {
    cout<< "Caught\n";
  }
  return 0;
} //end of main

When compiling i get the following errors

Function throw should have a prototype.

Undefined symbol "try"

Statement missing ;

Function should return a value.

Please help me.Thanks a lot

Compile with some non-ancient C++ compiler, use #include <iostream> instead of #include <iostream.h>, and drop #include <conio.h>, then it should just work once you have using std::cout;

It looks like you are missing

#include <exception>

Also, typically you should throw an object of a derived class from std::exception

UPDATE: Like the comments point out, including exception is not required. It is required for using std::exception only.

The fix is to use a different compiler. From wikipedia, Turbo C is a C compiler. Thus, it won't support C++ exception handling.

I think in turbo c if you point your cursor on anything and press F1 it gives the help. Try that with throw.

When you use turbo c , youll get this error. I dont know why, I tried different compiler like online gdb, it worked well there.

You cannot use iostream instead of iostream.h. Infact even string is not a data type according to turbo c