A more idiomatic way of doing this?

I'm doing a program and I would like to output a menu with two submenus in a module. I only want the main menu to show when you run the program. Then from the main menu be able to navigate to the submenus and back. If anyone could find a better way doing this (which I'm positive there is) please do say so. I'm not even sure this will work. Thanks!

module Menus

def self.getValidPositiveNumber
    input = gets.chomp

    while (input.to_i.to_s != input && input.to_f.to_s != input) do 
        puts "Ogiltig data. Försök igen."
        input = gets.chomp
    end

    # Är talet större än 0?
    number = input.to_f
    if (number <= 0)
        puts "you cant put that."
        getValidPositiveNumber
    end
    return number
end

def self.get_valid_input(valid_options)

    input = gets.chomp
    while (!valid_options.include?(input) && !valid_options.include?(input.to_i))   
        # både Range och Array har include?
        puts "no good, please choose something inbetween " + valid_options.inspect
        input = gets.chomp
    end
    return input

end


class Menu

    attr_reader  :valid_options_range, :menu_string

    def initialize(valid_options_range, menu_string)
        @valid_options_range = valid_options_range
        @menu_string = menu_string
    end



    def do_menu_action(action)
        raise "Has to be called to in any subclass!"
    end


    def to_s
        return @menu_string
    end
end

   MAIN_MENU = <<END 
 "---------------------------" 
   Welcome to Ruby Camping!
     Menu
  1. Checkin
  2. Checkout
  3. Lists
  4. Economy
  5. Exit

  What do you want to do?
 "---------------------------"
 END

 def make_menu_choice(choice)

 case choice
    when 1:
      $camping.check_in
    when 2:
       $camping.check_out
    when 3:
      $current_menu = LISTS_MENU
    when 4:
      $current_menu = ECONOMY_MENU
    when 5:
      exit
   end
 end


  LISTS_MENU = <<END
"---------------------------"   
 -- 1. List current guests --
 -- 2. List all guests --
 --                          --
 -- 0. Back to Main menu      --
 ------------------------------"
 END


 def make_menu_choice(choice) 
   case choice
    when 1:
      $camping
    when 2:
      $camping.all_guests
    when 0:
      $current_menu = MAIN_MENU
   end
  end

  ECONOMY_MENU = <<END
 "---------------------------"   
 -- 1. List current guests --
 -- 2. List all guests --
 --                          --
 -- 0. Back to Main menu      --
 ---------------开发者_运维技巧---------------"
 END

end    

puts Menus::MAIN_MENU 
if Menus == 3 then LISTS_MENU = Lists_Menu.new 
elsif Menus == 4 then ECONOMY_MENU = Economy_Menu.new
end
__END__

I won't write the code for you (sorry), but I would do it this way:

A generic menu class which can be supplied with menu items mapped to numbers and method name symbols...

Then I'd create a class which has methods for all menu items and would instanciate the Menu Class dynamically how I need it and supply it with the required information...

From the menu then the methods would be called in the way like

ClassHoldingMethods.method( methodname[entered_number] ).call

(in this case methodname is an array mapping indices to methods to be called when chosen and entered_number the already sanity-checked number from the user)

That would be much more clean, because the menu class would be flexible and you could easily add new menu pages...

You should consider using the commander gem, which includes the highline gem, both of which were designed to facilitate user input and validation.