Write large 4 byte integer as an unsigned, binary
I have integers which floats between values: 4000000000-4294967000 (which is less than int max for a 4 byte unsigned int)
and i want to save it to file, and then re-read value
$f = fopen($fileName, 'wb'); fwrite($f, pack('I', $value));
It is important that in file, value must be exact 4 byte unsigned int, because external devices will expect that format of data. But PHP stores that big values as float, and destroys binary representation.
How i can write that numbers to file in that format?
[EDIT] @FractalizeR thx this works i have:
protected static function handleUint($direction, $value)
{
if($direction == 'encode')
{
$first2bytes = intval($value / (256 * 256));
$second2bytes = intval($value - $first2bytes);
return pack('n2',开发者_如何学编程 $first2bytes, $second2bytes);
}
else
{
$arr = unpack('n2ints', $value);
$value = $arr['ints1'] * (256 * 256) + intval($arr['ints2']) - 1;
return $value;
}
}
But i dont quite understand, why i have to -1 on the returning value, and is this binary will be produced correct?
Well, split that 4 bytes number into 2 2-bytes numbers (integer divide by 256*256 to get the first word and subtract that value from original one to get the second one) and write in two packs.
Don't worry about it being a float. If it's between 2^31 and 2^32-1, you won't have any problems.
PHP floats have a 52-bit mantissa and so can store without precision loss 32-bit numbers.
You tell pack
to encode an integer and you pass it a float, it will convert the float into an integer. Floats whose value is an integer between 2^31 and 2^32-1, get converted to negative numbers on 32-bit machines:
$ php -r "var_dump((int) 4000000000);" int(-294967296)
On a 64-bit machine, you get an integer too:
$ php -r "var_dump((int) 4000000000);" int(4000000000)
But their byte representation is exactly the same. pack
will return the same on both:
$ php -r "var_dump(unpack('H*', pack('I', (float) 4000000000)));" array(1) { [1]=> string(8) "00286bee" }
If you want to split your int
up into 4 bytes you can do the following:
int x = 13434;
byte[] buff = new byte[] {
(byte)((x >> 24) & 0xff),
(byte)((x >> 16) & 0xff),
(byte)((x >> 8) & 0xff),
(byte((x) & 0xff)
}
The method used here is called bitwise operations.
See: http://en.wikipedia.org/wiki/Bitwise_operation
Hope this helped.
EDIT:
I think this is how you would do the same in PHP:
$arr = array(
((x >> 24) & 0xff),
((x >> 16) & 0xff),
((x >> 8) & 0xff),
(x & 0xff)
);
See: http://php.net/manual/en/language.operators.bitwise.php
Use bcmath() to work on your numbers, and for saving, do as FractalizeR said.
Generally, see Arithmetic with Arbitrarily Large Integers in PHP
精彩评论