PHP read each line

I have a <textfield> ($_POST['list']).

How can I get value of each line to an array key?

Example:

<textfield name="list">Burnett River: named by James Burnett, explorer
Campaspe River: named for Campaspe, a mistress of Alexander the Great
Cooper Creek: named for Charles Cooper, Chief Justice of South Australia 1856-1861
Daintree River: named for Richard Daintree, geologist
</textfield>

Should be converted to:

Array(
[Burnett River: named by James Burnett, explorer]
[Campaspe River: named for Campaspe, a mistress of Alexander the Great]
[Cooper Creek: named for Charles Cooper, Chief Justice of South 开发者_JAVA百科Australia 1856-1861]
[Daintree River: named for Richard Daintree, geologist]
)

Thanks.

Use explode function, then trim the result array (to get rid of any remaining \n, \r or any accidental spaces/tabs):

$lines = explode("\n", $_POST['list']);
$lines = array_map('trim', $lines);

This is the safest way to do it. It doesn't assume you can just throw away carriage return (\r) characters.

$list_string = $_POST['list'];

// \n is used by Unix. Let's convert all the others to this format

// \r\n is used by Windows
$list_string = str_replace("\r\n", "\n", $list_string);

// \r is used by Apple II family, Mac OS up to version 9 and OS-9
$list_string = str_replace("\r", "\n", $list_string);

// Now all carriage returns are gone and every newline is \n format
// Explode the string on the \n character.
$list = explode("\n", $list_string);

Wikipedia: Newline

You can use explode() and explode at the newline character\n.

$array = explode("\n", $_POST['list']);

explode("\n", $_POST['list'])