Replicate the functionality of Java's "Pattern.quote" in a JavaScript RegExp [duplicate]

This question already has answers here: Is there a RegExp.escape function in JavaScript? (18 answers) Closed 7 years ago.

In Java, you might try to make a regular expression that would match the UR开发者_JAVA技巧L stackoverflow.com using Pattern.compile("stackoverflow.com"). But this would be wrong because the . has special meaning in regular expressions. The easiest way to fix this is to write Pattern.compile(Pattern.quote("stackoverflow.com")) which comes out to: Pattern.compile("\\Qstackoverflow.com\\E") which "quotes" the entire string.

I want to do the same thing in JavaScript, but JavaScript's regular expressions don't assign any meaning to \Q and \E and it doesn't look like there is a JavaScript equivalent, so I'm not sure how to go about it. My first thought (see my answer below) is to just put a backslash before any character that has a special meaning in a JavaScript regex, but this seems potentially error-prone and I suspect that someone might know of a better way.

This is for a Firefox extension so Mozilla-specific solutions are okay.

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To elaborate on my suggestion, it would look something like this:

// A RegExp that matches all the characters which have a special meaning in a RegExp
var regexpSpecialChars = /([\[\]\^\$\|\(\)\\\+\*\?\{\}\=\!])/gi;

I'm not sure if this is quite right, since some characters (like ! and =) only seem to have special meaning in certain situations. But assuming that it is, then you would do

var quotedURL = url.replace(regexpSpecialChars, '\\$1');

to replace, for instance, all $'s with \$'s. Then you can just build the RegExp from quotedURL:

var myRegExp = new RegExp(quotedURL, 'gi');