Demonstrating string comparison with Java
I want to demonstrate with a few line of code that in Java, that to compare two strings (String
), you have to use equals()
instead of the operator ==
.
Here is something I tried :
public static void main(String Args[])开发者_JAVA百科 {
String s1 = "Hello";
String s2 = "Hello";
if (s1 == s2)
System.out.println("same strings");
else
System.out.println("different strings");
}
I was expecting this output : different strings
, because with the test s1 == s2
I'm actually comparing two references (i.e. addresses) instead of the objet's content.
But I actually got this output : same strings
!
Browsing the internet I found that some Java implementation will optimize the above code so that s1
and s2
will actually reference the same string.
Well, how can I demonstrate the problem using the ==
operator when comparing Strings (or Objects) in Java ?
The compiler does some optimizations in your case so that s1
and s2
are really the same object. You can work around that by using
String s1 = new String( "Hello" );
String s2 = new String( "Hello" );
Then you have two distinct objects with the same text content.
Well, how can I demonstrate the problem using the == operator when comparing Strings (or Objects) in Java ?
Here a way:
String s = "ab";
String t = new String("ab");
System.out.println(s == t); // false
Also be careful when comparing primitive wrappers and using auto-boxing: Integer (and Long) for instance caches (and re-uses!) the values -128..127. So:
Integer s = -128;
Integer t = -128;
System.out.println(s == t);
will print true
, while:
Integer s = -129;
Integer t = -129;
System.out.println(s == t);
prints false
!
JAVA maintains a String Pool in the heap space, where it tries to have multiple references for same values if possible.
Had you written :
String s1 = new String ("Hello");
String s2 = new String ("Hello");
it would have given you the output : "different strings".'new' keyword creates a new object reference while not giving new will first check the string pool for its existence.
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