how to check if a URL exists or not - error 404 ? (using php)
how t开发者_JAVA技巧o check if a URL exists or not - error 404 ? (using php)
<?php
$url = "http://www.faressoft.org/";
?>
If you have allow_url_fopen
, you can do:
$exists = ($fp = fopen("http://www.faressoft.org/", "r")) !== FALSE;
if ($fp) fclose($fp);
although strictly speaking, this won't return false only for 404 errors. It's possible to use stream contexts to get that information, but a better option is to use the curl extension:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.example.com/notfound");
curl_setopt($ch, CURLOPT_NOBODY, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_exec($ch);
$is404 = curl_getinfo($ch, CURLINFO_HTTP_CODE) == 404;
curl_close($ch);
The simplest one to check the 404/200 or etc..
<?php
$mylink="http://site.com";
$handler = curl_init($mylink);
curl_setopt($handler, CURLOPT_RETURNTRANSFER, TRUE);
$re = curl_exec($handler);
$httpcdd = curl_getinfo($handler, CURLINFO_HTTP_CODE);
if ($httpcdd == '404')
{ echo 'it is 404';}
else {echo 'it is not 404';}
?>
You could use curl which is a PHP library. With curl, you could query the page and then check for the error code called:
CURLE_HTTP_RETURNED_ERROR (22)
This is returned if CURLOPT_FAILONERROR is set TRUE and the HTTP server returns an error code that is >= 400.
From the CURL documentation at php.net:
<?php
// Create a curl handle to a non-existing location
$ch = curl_init('http://404.php.net/');
// Execute
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_exec($ch);
// Check if any error occured
if(curl_errno($ch))
{
echo 'Curl error: ' . curl_error($ch);
}
// Close handle
curl_close($ch);
?>
http://www.php.net/manual/en/function.curl-errno.php
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