Type inheritance in F#
I can't find the proper syntax for coding a type D that inherits a base class B (written in C#) and his constructors other than the base class implicit constructor:
C# code:
public class B
{
private int _i;
pri开发者_高级运维vate float _f;
public B()
{
_i = 0;
_f = 0.0f;
}
public B(int i)
{
_i = 0;
_f = 0.0f;
}
public B(int i, float f)
{
_i = i;
_f = f;
}
}
F# code:
type D() =
inherit B()
//how to inherit from other constructors ?
Thanks
I found a way to do it thanks this blog !
type D =
class
inherit B
new () = {
inherit B()
}
new (i : int) = {
inherit B(i)
}
new ((i,f) : int*single) = {
inherit B(i, f)
}
end
Yes, it's a bit cumbersome, but like Brian said it's not the majority of the cases.
EDIT: Actually, class/end keywords are not mandatory for that (so I take back what i said about cumbersomeness). As Brian said on his blog here, F# normally infers the kind of type being defined, making these tokens unnecessary/redundant.
type D =
inherit B
new () = {
inherit B()
}
new (i : int) = {
inherit B(i)
}
new ((i,f) : int*single) = {
inherit B(i, f)
}
From the docs: "The arguments for the base class constructor appear in the argument list in the inherit clause." For example:
type D(i: int) =
inherit B(i)
I am not sure if you can call different base class constructors from different F# constructors, because F# requires all constructors to go through the "primary" constructor (because the primary constructor arguments are in scope for the entire class, so they have to be initialised). In your case, you can get away with it because your base class has a maximal constructor:
type D(i : int, f : float) =
inherit B(i, f)
new(i : int) = D(i, 0.0)
new() = D(0, 0.0)
But for a base class without a maximal constructor I'm not sure this is possible.
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