jquery, run form
how to activate the button. If the condition is true, I want to send data through a method (POST).
<script>
$(document).ready(function(){
var count = 0;
if(count == 2)
{
//run form
}
});
</script>
</head>
<body>
<form action = "" method = "post">
<input type = "text" name = "name" />
<input type = "submit" id = "ok"/>开发者_JAVA百科
</form>
$(document).ready(function(){
var count = 0;
if(count == 2)
{
$("myform").submit(function(e){
//This function is called before form is posted
if(mycondition == true)
return true; //that will post the form
else
return false; // that will stop posting form
//Here you can also change values of input fields and also do
// validation on them.
// instead of return false you can also use e.preventDefault()
// that will stop this event to do what it usually does that
// is submit the form.
}).trigger("submit"); //if you want it to submit immediatly
}
});
OR if you dont wanna use form id then
$(document).ready(function(){
var count = 0;
if(count == 2)
{
$("body form").find(":input[type=submit][id=ok]").trigger("click");
}
});
<form action = "" method = "post">
<input type = "text" name = "name" />
<input type = "submit" id = "ok"/>
</form>
Try
$("#ok").trigger("click");
加载中,请稍侯......
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