How can I access an object property named as a variable in php?
A Google APIs encoded in JSON returned an 开发者_StackOverflowobject such as this
[updated] => stdClass Object
(
[$t] => 2010-08-18T19:17:42.026Z
)
Anyone knows how can I access the $t
value?
$object->$t
obviously returns
Notice: Undefined variable:
t
in /usr/local/...Fatal error: Cannot access empty property in /....
Since the name of your property is the string '$t'
, you can access it like this:
echo $object->{'$t'};
Alternatively, you can put the name of the property in a variable and use it like this:
$property_name = '$t';
echo $object->$property_name;
You can see both of these in action on repl.it: https://repl.it/@jrunning/SpiritedTroubledWorkspace
Correct answer (also for PHP7) is:
$obj->{$field}
Have you tried:
$t = '$t'; // Single quotes are important.
$object->$t;
I'm using php7 and the following works fine for me:
class User {
public $name = 'john';
}
$u = new User();
$attr = 'name';
print $u->$attr;
this works on php 5 and 7
$props=get_object_vars($object);
echo $props[$t];
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