Most concise way to insert array of bytes into List<Byte>?

In some code I'm creating a List of Bytes, and want to insert an array of bytes into the list as I am building it. What is the cleanest way of doing this? See 开发者_开发技巧code below - thanks.

public class ListInsert {
    public static byte[] getData() {
        return new byte[]{0x01, 0x02, 0x03};
    }

    public static void main(String[] args) {
        final List<Byte> list = new ArrayList<Byte>();
        list.add((byte)0xaa);
        list.add(getData()); // I want to insert an array of bytes into the list here
        list.add((byte)0x55);
    }
}

IF you have a Byte[] arr -- an array of reference types -- you can use Arrays.asList(arr) to get a List<Byte>.

IF you have a byte[] arr -- an array of primitives -- you can't use Arrays.asList(arr) to get a List<Byte>. Instead you'll get a one-element List<byte[]>.

That is, while a byte can be boxed to a Byte, a byte[] DOES NOT get autoboxed to Byte[]!
_{(also true for other primitives)}

So you have two choices:

• Just iterate over each byte in byte[] and add individually
• Use libraries
  • With Apache Commons Lang, you can convert byte[] to Byte[]
    • You can then Arrays.asList and addAll
  • With Guava can convert byte[] immediatelly to List<Byte>

The first option looks like this:

byte[] arr = ...;
for (byte b : arr) {
    list.add(b);
}

The second option with Guava looks like this:

// requires Guava
byte[] arr = ...;
list.addAll(Bytes.asList(arr));

This uses Bytes.asList from package com.google.common.primitives. The package has other conversion utilities for other primitives too. The entire library is highly useful.

With Apache Commons Lang, you can use Byte[] toObject(byte[]) from ArrayUtils:

// requires Apache Commons Lang
byte[] arr = ...;
list.addAll(Arrays.asList(ArrayUtils.toObject(arr)));

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• Performance impact of autoboxing
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This might not answer your question but it should be a good practice. If you are heavily manipulating an array of bytes, use the ByteBuffer instead. This class have many types of implementation which can give you the best performance & memory usage. One of them is the Direct ByteBuffer which some operations can run natively.

To put a byte or an array of bytes is as simple as eating a candy:

ByteBuffer.put(byte src);
ByteBuffer.put(byte[] src);
ByteBuffer.put(byte[] src, int offset, int length);

And the best thing is when you trying to get the bytes out: directly, no array copy's needed (you need to check the size though) :)

byte[] data = ByteBuffer.array();

Hope you change your mind :)

There is the Arrays.asList() method which exactly do that:

Arrays.asList(getData());

So in your case :

list.addAll(Arrays.asList(getData()));

Do you really need List<Byte>? I also thought so, but changed my mind. ByteArrayOutputStream was much better for me.

import java.io.ByteArrayOutputStream;
ByteArrayOutputStream bo = new ByteArrayOutputStream();
// fill in buf or get a single byte b
bo.write(buf, 0, bytesRead);
bo.write(b);
byte[] resultArray = bo.toByteArray();