Why can't my Java method change a passed variable? [duplicate]
I was kind of baffled when I saw the following code did not work as expected.
开发者_如何学运维I thought Java always passed variables by references into functions. Therefore, why can't the function reassign the variable?
public static void main(String[] args) {
String nullTest = null;
setNotNull(nullTest);
System.out.println(nullTest);
}
private static void setNotNull(String s) {
s = "not null!";
}
This program outputs null
.
References to objects are passed by value in Java so assigning to the local variable inside the method doesn't change the original variable. Only the local variable s
points to a new string. It might be easier to understand with a little ASCII art.
Initially you have this:
------------
| nullTest |
------------
|
null
When you first enter the method setNotNull you get a copy of the value of nullTest in s
. In this case the value of nullTest is a null reference:
------------ ------------
| nullTest | | s |
------------ ------------
| |
null null
Then reassign s:
------------ ------------
| nullTest | | s |
------------ ------------
| |
null "not null!"
And then leave the method:
------------
| nullTest |
------------
|
null
Java doesnt pass by reference, it passes the value of the reference. When you are assigning s="not null"
, you are reassigning that value.
I was hoping to do something like setNotNull(MyObject o) without using o = setNotNull(o)
Simply, you cannot. The closest you will get is something like this:
public class MyRef<T> {
private T obj;
public T get() {
return obj;
}
public void set(T obj) {
this.obj = obj;
}
public void setNotNull(T obj) {
if (this.obj == null) {
this.obj = obj;
}
}
}
MyRef<MyObj> ref = new MyRef<MyObj>();
ref.setNotNull(xyz);
System.err.println(ref.get());
which is all rather clunky, and probably not worth the effort.
s =
this is why. you are assigning to s, not modifying the object that s points to.
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