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find minimum of a function defined by integration in Mathematica

I need to find the minimum of a function f(t) = int g(t,x) dx over [0,1]. What I did in mathematica is as follows:

f[t_] = NIntegrate[g[t,x],{x,-1,1}]
FindMinimum[f[t],{t,t0}]

However mathematica halts at the first try, because NIntegrate does not work with the symbolic t. It needs a specific value to evaluate. Although Plot[f[t],{t,0,1}] works perferctly, FindMinimum stops at the initial point.

I cannot replace NIntegrate by Integrate, because the function g is a bit complicated and if you type Integrate, mathematica just keep开发者_开发百科 running...

Any way to get around it? Thanks!


Try this:

In[58]:= g[t_, x_] := t^3 - t + x^2

In[59]:= f[t_?NumericQ] := NIntegrate[g[t, x], {x, -1, 1}]

In[60]:= FindMinimum[f[t], {t, 1}]

Out[60]= {-0.103134, {t -> 0.57735}}

In[61]:= Plot[f[t], {t, 0, 1}]

Two relevant changes I made to your code:

  1. Define f with := instead of with =. This effectively gives a definition for f "later", when the user of f has supplied the values of the arguments. See SetDelayed.

  2. Define f with t_?NumericQ instead of t_. This says, t can be anything numeric (Pi, 7, 0, etc). But not anything non-numeric (t, x, "foo", etc).


An ounce of analysis...

You can get an exact answer and completely avoid the heavy lifting of the numerical integration, as long as Mathematica can do symbolic integration of g[t,x] w.r.t x and then symbolic differentiation w.r.t. t. A less trivial example with a more complicated g[t,x] including polynomial products in x and t:

g[t_, x_] := t^2 + (7*t*x - (x^3)/13)^2;
xMax = 1; xMin = -1; f[t_?NumericQ] := NIntegrate[g[t, x], {x, xMin, xMax}];
tMin = 0; tMax = 1;Plot[f[t], {t, tMin, tMax}];
tNumericAtMin = t /. FindMinimum[f[t], {t, tMax}][[2]];
dig[t_, x_] := D[Integrate[g[t, x], x], t];
Print["Differentiated integral is ", dig[t, x]];
digAtXMax = dig[t, x] /. x -> xMax; digAtXMin = dig[t, x] /. x -> xMin;
tSymbolicAtMin = Resolve[digAtXMax - digAtXMin == 0 && tMin ≤ t ≤ tMax, {t}];
Print["Exact: ", tSymbolicAtMin[[2]]];
Print["Numeric: ", tNumericAtMin];
Print["Difference: ", tSymbolicAtMin [[2]] - tNumericAtMin // N];

with the result:

⁃Graphics⁃
Differentiated integral is 2 t x + 98 t x^3 / 3 - 14 x^5 / 65
Exact: 21/3380
Numeric: 0.00621302
Difference: -3.01143 x 10^-9


Minimum of the function can be only at zero-points of it's derivate, so why to integrate in the first place?

  • You can use FindRoot or Solve to find roots of g
  • Then you can verify that points are really local minimums by checking derivates of g (it should be positive at that point).
  • Then you can NIntegrate to find minimum value of f - only one numerical integration!
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