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Compare the lengths arrays that have duplicates

I wish to determine whether there are any duplicates in two arrays, i.e. duplicates in array1 or duplicates in array2. If there are, then set a variable to equal 1, otherwise 0. I have the following code but it does not seem to work and I cannot understand why:

$a = count(array_unique($myarraydf));
$b = count($myarraydf);
$c = count(array_unique($myarrayds));
$d = count($myarrayds);

if (($a == $b) || ($c == $d)) {
$ties = 0;
   }
else {
    $ties = 1;
}
开发者_高级运维

where $myarraydf and $myarrayds are arrays of numeric values.


If you want to set $ties = 1 if there are duplicates in either set, you need to change your operator to AND:

if (($a == $b) and ($c == $d)) {

If you want to set $ties = 1 if both contain duplicates, then the OR is correct.


I suggest using array_diff, see: http://us3.php.net/array_diff

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