开发者

ERLANG - Splitting Lists into sub list

Hi this is my first post here hope you all are well. So Im just starting erlang and I ran into a problem im not sure how to tackle yet.

So I have a binary I am recieving in the form of

<<56, 23, 67, 34, 45, 78, 01, 54, 67, 87, 45, 53, 01, 34, 56, 78>>

My goal is to split it into a sub list (or binary if more efficient) based on the 01.

For example the above should come out looking like:

<<56, 23, 67, 34, 45, 78>> <<54, 67, 87, 45, 53>> <<34, 56, 78>>

-or-

[[56, 23, 67, 34, 45, 78], [54, 67, 87, 45, 53], [34, 56, 78]]

The 01 is the separating tag, it does not need to be included in the final output.

I have tried something as such: (PLEASE disregard if there is a better way)

parse1([]) -> [];
parse1(1) -> io:format("SOHSOHSOHSOHSOHSSOHSOHS");
parse1(Reply) -> parse1({Reply, []});
parse1({Reply, nxtParse}) ->
    [H | T] = Reply,
    case H of
         _ when H > 1 ->
            [H | nxtParse],
              io:format("Reply 1 = ~p~n", [H]),
            parse1({T, nxtParse});
         _ when H == 1 -> 
            io:format("SOHSOHSOHSOHSOHSSOHSOHS")开发者_如何学C;

        [] ->
            ok

    end.

This isn't really clean at all and doesn't resemble at all what pro's write. Im sure Ill smack my head "duh" when someone clues me in.

I realize there is definitely more than one solution, but what is the BEST one. It seems ERL has so many BIF's and way to do things, just gotta find my way around I guess.

Thanks for the help guys -B


Coming with R14A, Erlang now includes a binary module to handle such tasks:

1> Bin = <<56, 23, 67, 34, 45, 78, 01, 54, 67, 87, 45, 53, 01, 34, 56, 78>>.
<<56,23,67,34,45,78,1,54,67,87,45,53,1,34,56,78>>
2> binary:split(Bin, <<01>>, [global]).
[<<56,23,67,34,45,78>>,<<"6CW-5">>,<<"\"8N">>]

Note that although it looks wrong (<<"6CW-5">> and <<"\"8N">>), the underlying representation is right and the strings are the VM trying to figure out how to print out the binaries. See the same call when outputting in a raw format:

3> io:format("~w~n", [binary:split(Bin, <<01>>, [global])]).
[<<56,23,67,34,45,78>>,<<54,67,87,45,53>>,<<34,56,78>>]
ok
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜