SQL transform semi-colon list into relationship table
I currently have a code table containing a list of types (Type_ID, Description), but they are saved in another table as ID;;ID;;ID...etc
I am looking for a script that will take those ID's and place them in a relationship table c开发者_如何学Pythonorresponding to there Type ID
For example in table A the Type_ID entries could look like:
1;;2;;4
1 3;;4 1;;2;;3;;4
I am completely stumped on how to accomplish this and any help is appreciated.
First of all, I would probably recommend going the UDF route (so that you don't reinvent the wheel). However, given that this sounds like a one-off activity, you could just use the following:
declare @output table (parentKey int, value int)
declare @values table (idx int identity(1, 1), parentKey int, value varchar(255))
-- Modify the below query to capture the data from your table
insert into @values (parentKey, value) values(1, '1;;2;;4'),(2, '1'),(3, '3;;4'),(4, '1;;2;;3;;4')
declare @i int
declare @cnt int
select @i = MIN(idx) - 1, @cnt = MAX(idx) from @values
while(@i < @cnt)
begin
select @i = @i + 1
declare @value varchar(255)
declare @key int
select @value = value, @key = parentKey from @values where idx = @i
declare @idx int
declare @next int
select @idx = 1
while(@idx <= LEN(@value))
begin
select @next = CHARINDEX(';;', @value, @idx)
if(@next > @idx)
begin
insert into @output (parentKey, value) values(@key, SUBSTRING(@value, @idx, @next - @idx))
select @idx = @next + 2
end
else
begin
insert into @output (parentKey, value) values(@key, SUBSTRING(@value, @idx, LEN(@value) - @idx + 1))
select @idx = LEN(@value) + 1
end
end
end
select * from @output
The @output
table variable now contains the mapping you're looking for. You can either copy from that to your destination at the end, or you can remove @output
from the query and substitute equivalent inserts directly into your relationship table.
Probably the easiest way is to use a UDF
(User Defined Function), such as the Split functions outlined here.
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