php include gives an error
i want to include my php file but i get an error
my page contains javascript
this is the error i am getting
[Thu Aug 05 15:38:01 2010] [error] [client 10.0.0.2] <br/><br/>Unexpexted output: \r\n<html>\r\n\r\n\r\n\r\n<script language="javascript" type="text/javascript" src................
this is my server code , i am calling the page via ajax
function getPageContent(&$response){
$PAGE_URL = $_POST['PAGE_URL'];
try{
echo '../' . $PAGE_URL;
}catch(Exception $ee){
error_log($ee->getMessage());
}
$response->fields->frame_main = file_get_co开发者_StackOverflowntents('../' . $PAGE_URL);
}
thank you
Looks like you're trying to include a javascript file with PHP.. echo ' instead..
it looks like what you're trying to do is include a javascript file on demand. Without the full source (including what you're passing in the URL, it's a bit difficult to debug.
I feel like what you want to be saying here:
$response->fields->frame_main = file_get_contents('../' . $PAGE_URL);
is actually
$response->fields->frame_main = '../' . $PAGE_URL;
Since based on the output you've provided, it looks like you're accidentally reading the file into the tag, rather than providing the filename.
One small point I feel obligated to bring up. Your code in it's current implementation seems like it would allow me to pass a POST variable like "../../../../../etc/passwd" and retreive the contents of that file. If you do end up reading in files on demand from the user, please validate them fully. Filtering them using a function like basename() may be of use.
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