Shell script to get difference between two dates
If there are dates as 2010-06-01 and another as 2010-05-15
Using shell script or开发者_JAVA技巧 date command how to get the number of days between the two dates
Thanks..
Using only date and shell arithmetics:
echo $((($(date -d "2010-06-01" "+%s") - $(date -d "2010-05-15" "+%s")) / 86400))
There's a solution that almost works: use the %s
date format of GNU date, which prints the number of seconds since 1970-01-01 00:00. These can be subtracted to find the time difference between two dates.
echo $(( ($(date -d 2010-06-01 +%s) - $(date -d 2010-05-15 +%s)) / 86400))
But the following displays 0 in some locations:
echo $((($(date -d 2010-03-29 +%s) - $(date -d 2010-03-28 +%s)) / 86400))
Because of daylight savings time, there are only 23 hours between those times. You need to add at least one hour (and at most 23) to be safe.
echo $((($(date -d 2010-03-29 +%s) - $(date -d 2010-03-28 +%s) + 43200) / 86400))
Or you can tell date
to work in a timezone without DST.
echo $((($(date -u -d 2010-03-29 +%s) - $(date -u -d 2010-03-28 +%s)) / 86400))
(POSIX says to call the reference timezone is UTC, but it also says not to count leap seconds, so the number of seconds in a day is always exactly 86400 in a GMT+xx timezone.)
OSX date
is different than GNU date
. Got it working like this in OSX. This is not portable solution.
start_date=$(date -j -f "%Y-%m-%d" "2010-05-15" "+%s")
end_date=$(date -j -f "%Y-%m-%d" "2010-06-01" "+%s")
echo $(( ($end_date - $start_date) / (60 * 60 * 24) ))
Idea is still same as in the other answers. Convert dates to epoch time, subtract and convert result to days.
Got it
d1=`date +%s -d $1`
d2=`date +%s -d $2`
((diff_sec=d2-d1))
echo - | awk -v SECS=$diff_sec '{printf "Number of days : %d",SECS/(60*60*24)}'
thanks..
Gnu date knows %j to display the day in year:
echo $(($(date -d 2010-06-01 +%j) - $(date -d 2010-05-15 +%j)))
crossing year-boundaries will give wrong results, but since you gave fixed dates ...
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