why did it not split?
i am confused on why it doest not split the string? my array of string exp does not contain anything when i de开发者_运维问答bug it is the split wrong?what i am trying to do is to split a very simple expression like 1+2+3 and then parse the values, doing a calculator.
EDIT hi, why i am splitting on each character is because i am doing a calculator, and have read something about converting infix to postfix,so i need to split the string and then loop through each of the string and do the checking as shown below,however when i debug it shows the exp[] is empty
For each token in turn in the input infix expression:
* If the token is an operand, append it to the postfix output.
* If the token is an operator A then:
o While there is an operator B of higher or equal precidence than A at the top of the stack, pop B off the stack and append it to the output.
o Push A onto the stack.
* If the token is an opening bracket, then push it onto the stack.
* If the token is a closing bracket:
o Pop operators off the stack and append them to the output, until the operator at the top of the stack is a opening bracket.
o Pop the opening bracket off the stack.
When all the tokens have been read:
* While there are still operator tokens in the stack:
o Pop the operator on the top of the stack, and append it to the output.
// the main class
public class Main {
public static void main(String[] args) {
calcExpChecker calc = new calcExpChecker("1+2+3+4");
calc.legitExp();
calc.displayPostfix();
}
}
//the class
package javaapplication4;
import java.util.*;
public class calcExpChecker {
private String originalExp; // the orginal display passed
private boolean isItLegitExp; // the whole expression is it legit
private boolean isItBlank; // is the display blank?
private StringBuilder expression = new StringBuilder(50);
private Stack stack = new Stack();//stack for making a postfix string
calcExpChecker(String original)
{
originalExp = original;
}
//check for blank expression
public void isitBlank()
{
if(originalExp.equals(""))
{
isItBlank = true;
}
else
{
isItBlank = false;
}
}
//check for extra operators
public void legitExp()
{
String[] exp = originalExp.split(".");
for(int i = 0 ; i < exp.length ; i++)
{
if(exp[i].matches("[0-9]"))
{
expression.append(exp[i]);
}
else if(exp[i].matches("[+]"))
{
if(stack.empty())
{
stack.push(exp[i]);
}
else
{
while(stack.peek().equals("+"))
{
expression.append(stack.pop());
}
stack.push(exp[i]);
}
}
if (!stack.empty())
{
expression.append(stack.pop());
}
}
}
public void displayPostfix()
{
System.out.print(expression.toString());
}
}
If you make every character a delimiter, what is between them? Nothing
e.g., 1+2+3+4 is 1 a delimiter? yes, ok, capture everything between it and the next delimiter. Next delimiter? +. Nothing captured. Next delimiter? 2. etc etc
You want to split on every character, so rather use string.split("")
.
for (String part : string.split("")) {
// ...
}
Or better, just iterate over every character returned by string.toCharArray()
.
for (char c : string.toCharArray()) {
// ...
}
With chars you can use a switch
statement which is better than a large if/else
block.
why do you need to split on each character & rather not go for foreach character in the String. That way you don't have to reference as exp[i] either.
Anyways you can split using "" instead of "."
Confession:
Okay I guess my answer is bad because there are subtle differences between Java and C# with this stuff. Still, maybe it'll help someone with the same problem but in C#!
Btw, in C#, if you pass in a RegEx "." you don't get an empty array, instead you get an array of blanks (""), one for each character boundary in the string.
Edit
You can pass a regex expression into the split()
function:
string expressions = "10+20*4/2";
/* this will separate the string into an array of numbers and the operators;
the numbers will be together rather than split into individual characters
as "" or "." would do;
this should make processing the expression easier
gives you: {"10", "+", "20", "*", "4", "/", "2"} */
foreach (string exp in expressions.split(@"(\u002A)|(\u002B)|(\u002D)|(\u002F)"))
{
//process each number or operator from the array in this loop
}
Original
String[] exp = originalExp.split(".");
You should get at least one string from the return value of split()
(the original un-split string). If the array of strings is empty, the original string was probably empty.
- Java String Split() Method
精彩评论