XSL Transformation through code does not result in the same output as XSL transformation done through a tool
I am transforming my XML file to another XML file using the XslCompiledTransform classes available in the .NET framework 3.5
Here's my code.
private static void transformUtil(string sXmlPath, string sXslPath, string outputFileName)
{
try
{
XPathDocument myXPathDoc = new XPathDocument(sXmlPath);
XslCompiledTransform myXslTrans = new XslCompiledTransform();
//load the Xsl
myXslTrans.Load(sXslPath);
//create the output stream
XmlTextWriter myWriter = new XmlTextWriter(outputFileName, null);
//do the actual transform of Xml
myXslTrans.Transform(myXPathDoc, null, myWriter);
myWriter.Close();
}
catch (Exception e)
{
EventLogger eventLog;
eventLog = new EventLogger("transformUtil", e.ToString());
}
}
}
The code works, but the output file does not have the XML declaration in the header.
**<?xml version="1.0" encoding="utf-8"?>**
I a开发者_如何学Pythonm at a loss to understand this. When I use the same XSL file to transform the XML, using a tool like notepad++ or visual studio, the transformation contains the XML declaration in the header. So is XslCompiledTransform responsible for truncating this declaration? I am puzzled.
Anyone else facing similar issues?
My XSL file header looks like this.
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
The XML writer used does not have any settings associated with it.
change
//create the output stream
XmlTextWriter myWriter = new XmlTextWriter(outputFileName, null);
to
XmlWriterSettings settings =
new XmlWriterSettings
{
OmitXmlDeclaration = false
};
XmlWriter myWriter = XmlWriter.Create(outputFileName, settings);
Alternatively, you could do less to setup the transform:
private static void transformUtil(string sXmlPath, string sXslPath,
string outputFileName)
{
try
{
XslCompiledTransform xsl = new XslCompiledTransform();
// Load the XSL
xsl.Load(sXslPath);
// Transform the XML document
xsl.Transform(sXmlPath, outputFileName);
}
catch (Exception e)
{
// Handle exception
}
}
This should also honor the xsl:output instructions from the XSLT file itself, in particular the omit-xml-declaration
attribute, for which the default value is "no" if left unspecified.
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