Can I declare that a php function throws an exception?
Can I declare a function in php that throws an exception? For example:
public fun开发者_如何学编程ction read($b, $off, $len) throws IOException
You can use @throws in the PHPDoc comment, and the IDE will recognize this function as throwing an exception, when viewing the doc, however unlike Java it will not force you to implement the Try{}catch block. Maybe future versions of the IDE (I am using InteliJ 11) will mark those places where try{}catch is expected, that same as it already do with the JavaScript types marked by doc (e.g. String}) when recognizing inconsistency.
In short, using Doclet like when codding with scripting languages (PHP, JavaScript..), is turn to be complementary tool for safer programming in the case of non type-safe and non compiled languages.
like this:
enter code here
/**
* Handle 'get' operations
* @abstract
* @param int $status reference for setting the response status
* @param String $body reference for setting the response data
* @return mixed
* @throws Exception if operation fail
*/
function get(&$status, &$body) {
}
I misread the question, see the answer below from Gilad (which should be accepted).
Previous answer:
You could throw a new exception from the body of the function. It's all described here
Example:
<?php
function inverse($x) {
if (!$x) {
throw new Exception('Division by zero.');
}
else return 1/$x;
}
try {
echo inverse(5) . "\n";
echo inverse(0) . "\n";
} catch (Exception $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
// Continue execution
echo 'Hello World';
?>
For a list of exceptions that come with the SPL: SPL Exceptions.
If you want to create your own exception:
From the PHP Exceptions page:
The thrown object must be an instance of the Exception Class or a subclass of Exception. Trying to throw an object that is not will result in a PHP Fatal Error.
So yes, it is possible to create your own exceptions. Just a bit of reading will help you achieve what you want.
精彩评论