convert month from name to number

Is there an easy way to change $month = "July"; so that $nmonth = 7 (07 would be fine too). I could do a case statement, but surely there is already a function to convert? EDIT: I wish I could accept multiple answers, cause two of you basically ga开发者_StackOverflowve me what I needed by your powers combined.

$nmonth = date('m',strtotime($month));

That will give the numerical value for $month. Thanks!

Try this:

<?php
  $date = date_parse('July');
  var_dump($date['month']);
?>

Yes,

$date = 'July 25 2010';
echo date('d/m/Y', strtotime($date));

The m formats the month to its numerical representation there.

An interesting look here, the code given by kelly works well,

$nmonth = date("m", strtotime($month));

but for the month of february, it won't work as expected when the current day is 30 or 31 on leap year and 29,30,31 on non-leap year.It will return 3 as month number. Ex:

$nmonth = date("m", strtotime("february"));

The solution is, add the year with the month like this:

$nmonth = date("m", strtotime("february-2012"));

I got this from this comment in php manual.

$string = "July";
echo $month_number = date("n",strtotime($string));

returns '7' [month number]

Use date("m",strtotime($string)); for the output "08"

For more formats reffer this..
http://php.net/manual/en/function.date.php

you can also use this one:

$month = $monthname = date("M", strtotime($month));

$nmonth = date("m", strtotime($month));

$monthname = date("F", strtotime($month));

F means full month name

If you want number of month from string name then

$month = 'August';
$year = 2019;
echo date('m',strtotime($month.' '.$year));

Gives 08

Or If you want the Full name of the month then

echo date('F')

OR if you want the half name of the month then

echo date('M')

<?php
$monthNum = 5;
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10));
echo $monthName; //output: May
?>

It may be easiest to create a fake date so you can use the date function.

Excellent reference here: http://php.net/manual/en/function.date.php

Example:

<?
$month = 7;

$tempDate = mktime(0, 0, 0, $month, 1, 1900); 

echo date("m",$tempDate);


?>

Above answer is good. Here is another way to do:-

function getMonthNumber($monthStr) {
//e.g, $month='Jan' or 'January' or 'JAN' or 'JANUARY' or 'january' or 'jan'
$m = ucfirst(strtolower(trim($monthStr)));
switch ($m) {
    case "January":        
    case "Jan":
        $m = "01";
        break;
    case "February":
    case "Feb":
        $m = "02";
        break;
    case "March":
    case "Mar":
        $m = "03";
        break;
    case "April":
    case "Apr":
        $m = "04";
        break;
    case "May":
        $m = "05";
        break;
    case "June":
    case "Jun":
        $m = "06";
        break;
    case "July":        
    case "Jul":
        $m = "07";
        break;
    case "August":
    case "Aug":
        $m = "08";
        break;
    case "September":
    case "Sep":
        $m = "09";
        break;
    case "October":
    case "Oct":
        $m = "10";
        break;
    case "November":
    case "Nov":
        $m = "11";
        break;
    case "December":
    case "Dec":
        $m = "12";
        break;
    default:
        $m = false;
        break;
}
return $m;
}

Maybe use a combination with strtotime() and date()?

Use

date("F", mktime(0, 0, 0, ($month)));

where, $month value will be 1 -> 12

$date = 'Dec 25 2099';
echo date('d/m/Y', strtotime($date));

This returns 01/01/1970, that means php doesn't support all dates, it returns correct formatted date till Jan 19 2038 but Jan 20 2038 returns 01/01/1970

$dt = '2017-Jan-10';
         OR
$dt = '2017-January-10';

echo date('Y-m-d', strtotime($dt));

echo date('Y/m/d', strtotime($dt));

With PHP 5.4, you can turn Matthew's answer into a one-liner:

$date = sprintf('%d-%d-01', $year, date_parse('may')['month']);

I know this might seem a simple solution, but why not just use something like this

<select name="month">
  <option value="01">January</option>
  <option value="02">February</option>
  <option selected value="03">March</option>
</select>

The user sees February, but 02 is posted to the database