how to for every parent node select every not first child node in a tree with multiple parent nodes
His,
I think I've got a tricky questions for XPath experts. There is a node structure like this:
A(1)-|
|-B(1)
|-B(2)
|-B(3)
A(2)-|
|-B(2.1)
|-B(2.2)
|-B(2.3)
...
How to, with a single XPath-expression, extract only the following nodes
A(1)-|
|-B(2)
|-B(3)
A(2)-|
|-B(2.2)
开发者_如何学编程 |-B(2.3)
...
That is for every parent node its first child element should be excluded.
I tried A/B[position() != 1] but this would filter out only B(1.1) and select B(2.1).
Thanks
This XPath expression (no preceding-sibling::
axis used):
/*/a/*[not(position()=1)]
when applied on this XML document:
<t>
<a>
<b11/>
<b12/>
<b13/>
</a>
<a>
<b21/>
<b22/>
<b23/>
</a>
</t>
selects the wanted nodes:
<b12 />
<b13 />
<b22 />
<b23 />
This can be verified with this XSLT transformation, producing the above result:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select="/*/a/*[not(position()=1)]"/>
</xsl:template>
</xsl:stylesheet>
Tricky. You could select nodes that have preceding siblings:
A/B[preceding-sibling::*]
This will fail for the first element and succeed for the rest.
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