Get content of webservice

I've got an URL like here. When I type that into Safari's address bar I see an result like "Error" or "OK".

So, how do I properly call that URL from within my code and get that result as a开发者_StackOverflow中文版 string?

I've tried it with NSURLConnection, NSURLRequest and NSURLResponse but my response object is always nil.

The "response" in those classes refers to the protocol response (HTTP headers, etc.), not the content.

To get the content, you have a few options:

1. Use NSURLConnection in asynchronous mode: Using NSURLConnection

2. Use NSURLConnection in synchronous mode:

   // Error checks omitted
   NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
   NSURLRequest *request = [NSURLRequest requestWithURL:URL];
   NSData *data = [NSURLConnection sendSynchronousRequest:request
                                        returningResponse:nil
                                                    error:nil];
   

3. Use [NSString stringWithContentsOfURL:]

   NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
   NSString *content = [NSString stringWithContentsOfURL:URL];
   

Of course, you should use options 2 and 3 only if your content will be really small in size, to maintain responsiveness.