how to do nested generic classes (if that's the appropriate name) in csharp
I'd like to create a class of the following type
public class EnumerableDisposer<IEnumerable<IDisposable>>
But it won't let me declare it this way. I've also tried:
public class EnumerableDisposer<T> : IDisposable where T : IEnumerable<J> where J : IDisposable
But the compiler tells me that the type/namespace J could not be found.
What is it I have to do to create this cla开发者_StackOverflow社区ss?
You need to do:
public class EnumerableDisposer<T, J> : IDisposable
where T : IEnumerable<J> where J : IDisposable
{
// Implement...
Unfortunately, in order to wrap any internal type (IEnumerable<J>
, in your code), your "wrapping" class needs to have the type J
defined in the generic definition. In addition, in order to add the IEnumerable<J>
constraint, you need to have the other type T
.
That being said, if you want to avoid the double generic type specification, you could always rework this as follows:
public class EnumerableDisposer<T> : IDisposable
where T : IDisposable
{
public EnumerableDisposer(IEnumerable<T> enumerable)
{
// ...
This forces you to construct it with an IEnumerable<T>
where T is IDisposable, with a single generic type. Since you're effectively adding the IEnumerable<T>
constraint via the constructor, this will function as well as the previous option. The only downside is that you need to have the generic done at construction time, but given the name, I suspect this will be fine...
you need to definie J
.
eg
public class EnumerableDispose<T, J> : IDisposable
where T : IEnumerable<T>
where J : IDisposable
better would be:
public class EnumerableDispose<T> : IEnumerable<T>, IDisposable
where T : IDisposable
{
public EnumerableDispose(IEnumerable<T> source)
{
// TODO: implement
}
}
You can do this by adding an extra J
type parameter:
public class EnumerableDisposer<T, J> : IDisposable
where T : IEnumerable<J>
where J : IDisposable
Note that these T
and J
parameters are independent of any parameters in the outer class, even if they have the same names.
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