Strip leading spaces only
Given element:
<comments>开发者_如何学Go comments
go here
</comments>
How can I strip what may be multiple leading space characters. I cannot use normalize space because I need to retain newlines and such. XSLT 2.0 ok.
In XPath 1.0 (means XSLT 1.0, too):
substring($input,
string-length(
substring-before($input,
substring(translate($input, ' ', ''),
1,
1)
)
) +1
)
Wrapped in an XSLT transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:variable name="input"
select="string(/*/text())"/>
<xsl:template match="/">
'<xsl:value-of select=
"substring($input,
string-length(
substring-before($input,
substring(translate($input, ' ', ''),
1,
1)
)
) +1
)
"/>'
</xsl:template>
</xsl:stylesheet>
when this transformation is applied on the following XML document:
<t> XXX YYY Z</t>
the correct, wanted result is produced:
'XXX YYY Z'
Use the replace()
function:
replace($input,'^ +','')
That handles leading space characters only up to the first non-space. If you want to remove all leading whitespace characters (i.e. space, nl, cr, tab) up to the first non-whitespace, use:
replace($input,'^\s+','')
精彩评论