How to make a node result be different depending on the existence of a certain node using XLST?

My system produces a XML that contain a node that, depending on the type of event, came with different name. 开发者_高级运维The name can be <floatRate> or <fixedRate>. The path is always the same, only the node name that is different.

I need a transformation that can populate one field based on that name. The field will be called <type> and the contend must be float or fixed, based on the node name. Can this be done?

This transformation:

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="fixedRate|floatRate">
   <type><xsl:value-of select=
           "substring-before(name(),'Rate')"/></type>
 </xsl:template>
</xsl:stylesheet>

when applied on this XML document:

<rates>
    <fixedRate>2.3</fixedRate>
    <floatRate>1.1</floatRate>
</rates>

produces the wanted result:

<rates>
   <type>fixed</type>
   <type>float</type>
</rates>

Select/mach expressions can do boolean "or", as in

match="floatRate|fixedRate"

Edit your question and add samples of input, expected output and what you've already tried to get more help

Suppose we have this document as input:

<result>
    <floatRate>1.1</floatRate>
</result>

This stylesheet:

<xsl:stylesheet
          xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
          version="1.0">
    <xsl:template match="result">
        <type>
        <xsl:value-of select="substring-before(name(floatRate|fixedRate),'Rate')"/>
        </type>
    </xsl:template>
    <xsl:template match="text()"/>
</xsl:stylesheet>

Output:

<type>float</type>