How to get a time for the dates?
Table1
ID Date Time Functionkey
001 23-02-2009, 08:00:00 A
001 23-02-2009, 12:00:00 A
001 23-02-2009, 13:00:00 B
001 23-02-2009, 14:00:00 B
001 23-02-2009, 16:00:00 C
001 23-02-2009, 17:00:00 C
001 23-02-2009, 19:00:00 D
001 23-02-2009, 21:00:00 D
001 24-02-2009 10:00:00 A
001 24-02-2009 18:00:00 D
001 25-02-2009 09:00:00 A
001 25-02-2009 12:00:00 B
001 25-02-2009 18:00:00 D
....,
I want to get min(time) where function key = 'A', max(time) where function key = 'B', min(time) where function key ='c'. max(time) where function key = 'D' Query:
SELECT
ID, Date,
CASE WHEN function = 'A' THEN min(time) END as Intime1,
CASE WHEN function = 'B' THEN max(time) END as Outtime1,
CASE WHEN function = 'C' THEN min(time) END as Intime2,
CASE WHEN function = 'D' THEN max(time) END as Outtime2
FROM dbo.table1
GROUP BY id, date, function
Getting Output
ID Date, Intime1, Outtime1, Intime2, Outtime2
001 23-02-2009 08:00:00, null, null, null
001 23-02-2009 null, 14:00:00, null, null
001 23-02-2009 nul开发者_开发百科l, null, 16:00:00, null
001 23-02-2009 null, null, null, 21:00:00
...,
I need output in one line, How to make a query
ID Date, Intime1, Outtime1, Intime2, Outtime2
001 23-02-2009 08:00:00, 14:00:00. 16:00:00, 21:00:00
001 24-02-2009 09:00:00 null, null, 18:00:00
001 25-02-2009 09:00:00, 12:00:00, null, 18:00:00
...,
How to modify my query?
Try something like:
SELECT T1.ID, T1.Date, MIN(T1.Time) As Intime, MAX(T2.Time) AS Outtime
FROM Table1 T1
JOIN Table1 T2 ON T1.ID=T2.ID AND T1.Date=T2.Date
WHERE T1.Function = 'A' AND T2.Function='D'
GROUP BY T1.ID, T1.Date
Edit: Regarding your comment you just need to change the condition for table T1 with the function for the minimum (see the MIN(T1.Time) above) and the condition for table T2 with the function for the maximum (see MAX(T2.Time) above), so it should be:
SELECT T1.ID, T1.Date, MIN(T1.Time) As Intime, MAX(T2.Time) AS Outtime
FROM Table1 T1
JOIN Table1 T2 ON T1.ID=T2.ID AND T1.Date=T2.Date
WHERE T1.Function = 'C' AND T2.Function='D'
GROUP BY T1.ID, T1.Date
I hope I understood correctly from the comment what you need.
Edit 2: OK, I got it now. You need to do the same self join two more times like this:
SELECT
T1.ID, T1.Date,
MIN(T1.Time) AS Intime1,
MAX(T2.Time) AS Outtime1,
MIN(T3.Time) AS Intime2,
MAX(T4.Time) AS Outtime2
FROM Table1 T1
JOIN Table1 T2
ON T1.ID=T2.ID AND T1.Date=T2.Date
JOIN Table1 T3
ON T1.ID=T3.ID AND T1.Date=T3.Date
JOIN Table1 T4
ON T1.ID=T4.ID AND T1.Date=T4.Date
WHERE
T1.Func = 'A'
AND T2.Func='B'
AND T3.Func='C'
AND T4.Func='D'
GROUP BY
T1.ID, T1.Date
Edit 3: To account for possible missing values try the next query. The only value that needs to be present is that for the function 'A'. The rest can be absent:
SELECT
T1.ID, T1.Date,
MIN(T1.Time) AS Intime1,
MAX(T2.Time) AS Outtime1,
MIN(T3.Time) AS Intime2,
MAX(T4.Time) AS Outtime2
FROM Table1 T1
LEFT JOIN Table1 T2
ON T1.ID=T2.ID AND T1.Date=T2.Date AND T2.Func = 'B'
LEFT JOIN Table1 T3
ON T1.ID=T3.ID AND T1.Date=T3.Date AND T3.Func = 'C'
LEFT JOIN Table1 T4
ON T1.ID=T4.ID AND T1.Date=T4.Date AND T4.Func = 'D'
WHERE
T1.Func = 'A'
GROUP BY
T1.ID, T1.Date
One thing you really should consider, is to store your date/time as a single column formatted as a unix timestamp, it makes handling date/time a lot easier.
Try the following:
SELECT ID,
Date,
min(time) AS Intime,
max(time) AS Outtime
FROM table1
GROUP BY id, date
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